the product of two consecutive odd integers is 77 more than twice the larger integer. find the integers.

Step-by-step explanation:

Consecutive odd integers increase by 2 so:

Let the first integer be y,

The Second will be y+2

Therefore y×y+2=77+2(y+2)

y²+2y=77+2y+4

Move all the terms to one side NB:when the terms move over they change thier sign

y²+2y-81-2y=0

y²+2y-2y-81=0

y²-81=0

y²=81

Take square root

Y=9

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

5.25 ounces

step-by-step explanation:

divided 3/4 and 6