What are three equivalent expressions for 3x+3(x+y)

3 x + 3 (x + y)

3 (2 x + y)

6 x + 3 y

y = -2 x

y = -2 x (3 (x + y) + 3 x) = 6

(3 (x + y) + 3 x) = 3

(3 x + 3 (x + y)) dx = 3 (x^2 + x y) +

(x^2 + y^2<R^2)(3 (x + y) + 3 x) dx dy = 0

(3 x + 3 (x + y)) dy dx = 0

Step-by-step explanation:

Hope this helps ツ

the answer to this question is in the pic

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: