Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. xy = 6
(a) Find dy/dt, given x = 4 and dx/dt = 11.
dy/dt =

(b) Find dx/dt, given x = 1 and dy/dt = –9.
dx/dt =

A)

B)

Step-by-step explanation:

x and y are differentiable functions of t, and we are given the equation:

First, let's differentiate both sides of the equation with respect to t. So:

By the Product Rule and rewriting:

Therefore:

A)

We want to find dy/dt when x = 4 and dx/dt = 11.

Using our original equation, find y when x = 4:

Therefore:

Solve for dy/dt:

B)

We want to find dx/dt when x = 1 and dy/dt = -9.

Again, using our original equation, find y when x = 1:

Therefore:

Solve for dx/dt:

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

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