Simplify the expression.
(–2 –2i)(–4 + 6i) (1 point)
8 – 4i
8 – 12i
20 – 4i
–4 – 4i

simplify the expression.
(5 – 5i) – (–6 – 3i) (1 point)
–1 – 8i
11 – 2i
–11 + 2i
9i

Evaluate the expression. (9 + 5)(3 + 2)0

In a test for esp (extrasensory perception), a subject is told that cards only the experimenter can see contain either a star, a circle, a wave, or a square. as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. a subject who is just guessing has probability 0.25 of guessing correctly on each card. a. the count of correct guesses in 20 cards has a binomial distribution. what are n and p? b. what is the mean number of correct guesses in 20 cards for subjects who are just guessing? c. what is the probability of exactly 5 correct guesses in 20 cards if a subject is just guessing?

Rachel is studying the population of a particular bird species in a national park. she observes every 10th bird of that species that she can find in the park. her conclusion is that the birds living in the park who belong to that species generally feed on insects. rachel's sample is . based on the sample she picked, rachel's generalization is . reset next