Find the coordinates for the vertex of the graph of the function y = 3x^2- 12x + 12

First, you have to put the graph in vertex form by factoring. there is a GCF of 3, so take it out of the equation.
3(x²-4x+4).
now do bottoms up method.
1 × 4= 4, and -4 is the middle number.
-2 and -2 multiply to 4 and add up to -4.
factor: 3(x-2)(x-2). vertex form 3(x-2)²
vetex coordinates: (2,0) 

step-by-step explanation:

12 minutes