The figure shows two triangles on a coordinate grid:

what set of transformations is performed on triangle abc to form triangle a’b’c’?

a 180-degree counterclockwise rotation about the origin followed by a translation 5 units down

a translation 5 units down followed by a 180-degree counterclockwise rotation about the origin

a 270-degree counterclockwise rotation about the origin followed by a translation 5 units to the right

a translation 5 units to the right followed by a 270-degree counterclockwise rotation about the origin

A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin .

Step-by-step explanation:

From the given figure, the coordinates of ΔABC are A(-3,4), B(-3,1), C(-2,1) and the coordinates of ΔA'B'C' are A'(3,1), B'(3,4), C'(2,4).

When, a translation of 5 units down is applied to  ΔABC, the coordinates of the image will be

Then applying 180° counterclockwise rotation about the origin, the coordinates of the image will be :-

which are the coordinates of ΔA'B'C'.

Hence, the set of transformations is performed on triangle ABC to form triangle A’B’C’ is " A translation 5 units down followed by a 180-degree counterclockwise rotation about the origin ".

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)