Acompany has started selling a new type of smartphone at the price of $110-0.1x where x is the number of smartphones manufactured per day. the parts for each phone cost $50 and labor and overhead for running the plant cost $4000 per day. how many smartphones should the company manufacture and sell per day to maximize profit?

My solution to the problem is as follows:

x=number of phones
 
per dayselling price per day:p(x)=110−0.1x

cost price per day:c(x)=50x+4000

profit:P(x)=p(x)−c(x)

I hope my answer has come to your help. God bless and have a nice day ahead!

Hello there.

A company has started selling a new type of smartphone at the price of $110-0.1x where x is the number of smartphones manufactured per day. the parts for each phone cost $50 and labor and overhead for running the plant cost $4000 per day. How many smartphones should the company manufacture and sell per day to maximize profit?

profit:P(x)=p(x)−c(x)

Ifound this on google “a skewed (non-symmetric) distribution is a distribution in which there is no such mirror-imaging. a "skewed right" distribution is one in which the tail is on the right side. a "skewed left" distribution is one in which the tail is on the left side. the above histogram is for a distribution that is skewed right.” i hope this you for what your looking for