Conner and jana are multiplying (3^5 6^8)(3^9 6^10).
conner's work
(3^5 6^8)(3^9 6^10) = 3^5+^9 6^8+^10 = 3^14 6^18

jana's work
(3^5 6^8)(3^9 6^10) = 3^5⋅9 6^8⋅10 = 3^45 6^80
is either of them correct? explain your reasoning.
(i dont rly get this question)

Step-by-step explanation:

The given expression is

To solve this products, we need to use power properties, like the one below

In words, the product between powers which have the same base, results in the same base and the exponent is the sum of the first two.

So, if we apply this property, we have

Now, if we compare Conner's work and Jana's work, you will observe that Conner is right, because he applied the right property of powers to simplify the expression.

Therefore, Conner's work is right.

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column