Apyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6. find the lateral area of the pyramid.

a. 144 sq. units
b. 48√(10) sq. units
c. 72 sq. units

Option C is correct

the lateral area of the pyramid is, 72 sq. units

Step-by-step explanation:

Lateral surface area(S) of the pyramid is given by:

As per the statement:

A pyramid has a regular hexagonal base with side lengths of 4 and a slant height of 6.

⇒ units, slant height = 6 units

Substitute in [1] we have;

square units

Therefore,  the lateral area of the pyramid is, 72 sq. units

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

10 you would take 50/ .2

step-by-step explanation: