The table shows the distance randy drove on one day of her vacation. find the distance randy would have gone if she had driven for one more hour at the same rate. explain how you solved the problem.

I found the table that accompanies this problem:

Time(h)                1       2        3      4       5
Distance (mi)    55   110   165  220  275

speed = distance / time
speed = 55/1 = 55 miles per hour

speed = 110/2 = 55 miles per hour
speed = 165/3 = 55 miles per hour
speed = 220/4 = 55 miles per hour
speed = 275/5 = 55 miles per hour

distance = speed * time
distance = 55 miles per hour * 6 hours
distance = 330 miles.

To get the distance traveled, simply multiply the speed by the number of hours spent travelling.

The answer is: a = about 63.59ft2 for 15