What are the zeros of the function?

h(x)=x^3−2x^2−3x

select each correct answer.

x=−3

x=−1

x = 0

x = 1

x = 3

-1, 0, and 3

Step-by-step explanation:

I just took the test

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1