Awagon filled with groceries weighing 36 pounds begins to roll down a hill having an incline of 300. what force is required to keep the wagon from sliding down the hill?

18 lbs

Step-by-step explanation:

We are given that a wagon filled with groceries weighing 36 pounds begins to roll down a hill having an incline .

We have to find the value of force required to keep the wagon from sliding down the hill

Weight of wagon filled with groceries=36 pounds

Then, the force is required=

Substitute the values then we get

F=18 lbs

Hence, the force  required to keep the wagon from sliding down the hill=18 lbs

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.