An airplane flying into a headwind travels 1160 miles in 4 hours and 50 minutes. on the return flight, the distance is traveled in 4 hours. find the airspeed of the plane and the speed of the wind, assuming that both remain constant.

Let airspeed of the plane be x mph and wind speed = y mph. Then we have the following system of equations

x - y = 1160 /  4.833 =  240.0166
and 
x + y = 1160 / 4 = 290

adding the 2 equations:-

2x = 530.0166

x = 265 mph  = airspeed of the plane

y = 290 - 265 =  25 mph = speed of the wind

Ithink the answer is b i hope it my friend message me if i’m wrong and i’ll change my answer and fix it for you