What is f(–3) for the function f(a) = –2a2 – 5a + 4?

The given function is f(a)=)

The question is asking us to find f(-3)

To find f(-3) we replace a by -3.

f(-3)=

f(-3) =-2(9)+15+4

f(-3)=-18+15+4

f(-3)= -18+19

f(-3)= 1

The value of f(–3) for expression  f(a) = –2a² – 5a + 4 is 1 .

Step-by-step explanation:

As given the expression in the question be as follow.

f(a) = –2a² – 5a + 4

Put a = -3 in the above value

f(-3) = –2 × -3 × -3 – 5 × -3 + 4

f(-3) = - 18 + 15+ 4

f(-3) = - 3 + 4

f(-3) = 1

Therefore the value of f(–3) for expression  f(a) = –2a² – 5a + 4 is 1 .

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form