Given the above, which method would you use to prove abd ≅ acd? aas sss asa the two triangles are not congruent.

SSS rule of congruency

Step-by-step explanation:

It is given that ΔABC is isosceles triangle and ΔBDC is also isosceles triangle.

Thus, AB=AC and BD=DC.

Now, consider ΔABD and ΔACD, we have

AB=AC (Because  ΔABC is isosceles triangle)

AD=AD(Common side of both triangles)

BD=DC(Because  ΔBDC is isosceles triangle)

Therefore, by SSS congruency rule,

ΔABD≅ΔACD

Hence proved.

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

the system of inequalities is

step-by-step explanation:

step 1

find the equation of the dashed line

we have the points

(0,0) and (3,1)

the line passes through the origin, so, is a direct variation

find the slope

the equation of the dashed line is

the solution of the inequality a s the shaded area above the dashed line

therefore

the equation of the inequality a is

step 2

find the equation of the solid line

we have the points

(4,0) and (0,4)

find the slope

the equation of the solid line is

the solution of the inequality b s the shaded area below the solid line

therefore

the equation of the inequality b is

step 3

the system of inequalities is