Water flows back and forth between a small and large tank. when water is moving into a tank the flow rate is positive, and when water is moving from a tank the flow rate is negative. the large tank begins with 300 gallons of water, and the small tank begins with 200 gallons of water. after a period of 5 minutes, the large tank has the same amount of water as the small tank. which statement describes the flow rate?

the flow rate of the large tank is 10 gal/min, and the flow rate of the small tank is –10 gal/min.

the flow rate of the large tank is –10 gal/min, and the flow rate of the small tank is 10 gal/min.

the flow rate of the large tank is 20 gal/min, and the flow rate of the small tank is –20 gal/min.

the flow rate of the large tank is –20 gal/min, and the flow rate of the small tank is 20 gal/min.

large tank = 300

small tank = 200

300-200 = 100 gallon difeerence

 for both tanks to have the same amount of water

100/2 = 50 gallons

small tank 200 + 50 = 250

large tank 300-50 = 250

 50/5 = 10 gallons per minute

 so it is one of the first two answers

 s the large tank lost water so it would be negative, small tank increased so it would be positive

 so large tank would be -10 small tank would be 10

 so second answer

B

and for all you chums

the second one

Step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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step-by-step explanation: