Deanna has 4 quarters, 3 dimes, and 3 nickels in her purse. she reaches into her purse and randomly grabs two coins, one at a time. what is the probability deanna will first grab a quarter and then, without replacing it, grab a nickel?

Your answer would be 1/10

Step-by-step explanation:

step 1: 3/10 * 3/9

step 2: simplify these to get 1/10

answer: 0,6

step-by-step explanation:

this would make it the y intercept.

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560