Acircle is centered at the point (-7, -1) and passes through the point (8, 7). the radius of the circle is units. the point (-15, ) lies on this circle. nextreset

hello :
an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a = -7  and b = -1 (Center at: A(-7,-1) )
r = AP P(8,7)
r² = (AP)²
r² = (8+7)² +(7+1)² =225+64=289 so : r = 17
an equation of the circle that satisfies the stated conditions.
Center at  A(-7,-1), passing through P(8, 7) is :  

(x+7)² +(y+1)² = 289

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

13

step-by-step explanation:

divide the cost of the total of sodas you bought by the cost of one soda, for example:

$24.57 divided by $1.89 is 13 which means you bought 13 sodas