Anumber cube is rolled and a coin is tossed. what is the probability that a number greater than four is rolled and the coin comes up heads?

there are 6 numbers on a cube

there are 2 numbers greater than 4

 so a 2/6 reduced to 1/3 probability

there is a 1/2 probability of getting heads

1/3 x 1/2 = 1/6 probability of getting the wanted results

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: your gay

step-by-step explanation:

you dont know math