How many ounces of a 35% alcohol solution must be mixed with 10ounces of 40% alcohol solution to make a 37% alcohol solution?

First off, let's change the format of the percentage to decimal.. so 35% is just 35/100 or 0.35 and 40% is 40/100 or 0.4 and so on.



now, whatever "x" amount is, we know that x + 10 must add up to "y". x + 10 =  y, because both quantities added will give the mixture amount.

and whatever 0.35x + 4 = 0.37y, because both concentrated amounts must give the 37% of the mixture.



solve for "x", to see how much of the 35% solution will be needed.

what about "y"? well, x + 10 = y.