A person leans over a cliff that is 1000 feet high and throws a rock vertically upward at a speed of 200 ft/sec. When it falls, it barely misses the cliff and falls on the ground at the base of the cliff. The height of the rock (in feet) above the ground t seconds after it was thrown is given by the function f(t) = −16t2 + 200t + 1000. Determine when the rock will hit the ground at the base of the cliff.

answer: 38.47 is your answer

step-by-step explanation: hope i you and who ever sees this answer have a great rest of your day : )

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

step-by-step explanation: