Find the area inside the 26m square and outside the circle. Use 3.14 for π. A circle is fully inside a square with sides of length 26 meters, such that the circle touches the center of each side of the square.

A(b) = 145,34 m²

Step-by-step explanation:

Area of the square of side l = 26 m    A(s) = l²      A(s) = (26)²

A(s) = 676 m²

Areaof the circle of radius r = 13  A(c) = π*(r)²  A(c) = π*(13)²

A(c) = 169*π  m²

Then the area outside the circle and inside the square  A(b), is the difference between the area of the square minus the area of the circle, that is:

A(b) = A(s)  -  A(c)  =  676  - 169*π    m²

A(b) = 676  -  530,66  m²

A(b) = 145,34 m²

6 equilateral triangles