A car radiator needs a 40​% antifreeze solution. The radiator now holds 14 liters of a 30​% solution. How many liters of this should be drained and replaced with​ 100% antifreeze to get the desired​ strength?

2.03 liters of 30% antifreeze should be drained and replaced with 100% antifreeze to get the desired strength.

Step-by-step explanation:

Since a car radiator needs a 40% antifreeze solution, and the radiator now holds 14 liters of a 30% solution, to determine how many liters of this should be drained and replaced with 100% antifreeze to get the desired strength the following calculation must be performed:

100 x 0.3 + 0 x 1 = 30

90 x 0.3 + 10 x 1 = 37

85 x 0.3 + 15 x 1 = 40.5

86 x 0.3 + 14 x 1 = 39.8

85.8 x 0.3 + 14.2 x 1 = 39.94

85.7 x 0.3 + 14.3 x 1 = 40.01

85.71 x 0.3 + 14.29 x 1 = 40

100 = 14

14.29 = X

14.29 x 14/100 = X

200.06 / 100 = X

2.03 = X

Therefore, 2.03 liters of 30% antifreeze should be drained and replaced with 100% antifreeze to get the desired strength.

answer:

c. the third graph