The fracture strength of tempered glass averages 13.7 (measured in thousands of pounds per square inch) and has standard deviation 2. (a) What is the probability that the average fracture strength of 100 randomly selected pieces of this glass exceeds 13.9

0.15866

Step-by-step explanation:

Given :

μ = 13.7

x = 13.9

Sample size, n = 100

Standard deviation, σ = 2

Recall:

Z = (x - μ) ÷ σ/√n

Z = (13.9 - 13.7) ÷ 2/√100

Z = 0.2 ÷ 0.2

Z = 1

P(x > 13.9) = p(Z > 1) = 0.15866

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq