The graph to the right is a function of the form y=A cos(Bx – C) + D, B>0. The five quarter points of one cycle of the graph from right to left are (-π/3, -2), (π/6, 2), (2π/3, 6), (7π/6, 2) & (5π/3, -2). These five quarter points on the graph correspond to the five quarter points on the graph of y = cos x over the interval (0, 2π). Determine the equation of the specific function that is represented by the given graph based on the association of the labeled quarter points and the quarter points of the graph of y= cos x over the interval (0,2 π) What is the function of the form y=A cos (BX-C) +D where B>0 and -π

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

6: 07 is your answer

step-by-step explanation:

the answer is b.

surface area: 169π

volume: 366π

i got it down.