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How many moles are there in 993.6 grams of potassium sulfate (K2SO4)?​

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[Given] 993.6 g K₂SO₄

[Solve] moles K₂SO₄

[PT] Molar Mass of K: 39.10 g/mol

[PT] Molar Mass of S: 32.07 g/mol

[PT] Molar mass of O: 16.00 g/mol

1. [DA] Set up:

2. [DA] Divide [Cancel out units]:

Follow sig fig rules and round. We are given 4 sig

figs.

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Hope it helps

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Solution given:

K₂SO₄➙1mole

K₂SO₄➙39*2+32+16*4=174g

we have

174g➙1mole

993.6g➙=5.7mole

5.7moles are there in 993.6 grams of potassium sulfate (K2SO4).

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step-by-step explanation: