Use the box method to distribute and simplify (6x-4)(-x^2+2x-3). Drag and drop the terms to the correct locations of the table. (6x-4)(-x^2+2x-3)

answer: y=0 if that is what u r looking for

explanation:

remove parenthesis:

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apply rule

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multiply fractions:

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divide:

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mordancy.

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

what am i trying to find out. you didn't put up the whole question.

step-by-step explanation: