solve the simultaneous linear algebra quadratic equation 2x-y=8 3x-y=17​

2x-y=8

(3x-y=17)*_1

2x-y=8

-3x+y=-17

#-x=-9, x=9 & y=-10

x = 9  and y  = 10

Step-by-step explanation:

Subtract the second equation from 1 as in doing so the y will get cancelled as they are of the opposite sign.

2x - y = 8

-3x + y = -17

- x = - 9

Therefore,

x = 9

Now we will add the value of x to any of the equation from the question.

2x - y = 8

2(9) - y = 8

18 - y = 8

Therefore,

y = 10

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

step-by-step explanation:

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