Write an equation for the line that contains (-15, -8) and is parallel to the graph -3x + 5y = -8

y=3/5x+1

Step-by-step explanation:

Hi there!

We are given the equation -3x+5y=-8 and we want to find the equation of the line that is parallel to -3x+5y=-8 and contains the point (-15,-8)

parallel lines have the same slopes, but different y intercepts.

So let's first find the slope of -3x+5y=-8

We can do this by converting the equation from standard form (ax+by=c where a, b, and c are free coefficients (numbers)) to slope-intercept form (y=mx+b, where m is the slope and b is the y intercept)

add 3x to both sides

5y=3x-8

divide by 5 on both sides

y=3/5x-8/5

3/5 is in the place of where m is, so that means that 3/5 is the slope of the line

we can write the equation of the new line in slope-intercept form.

Here it is so far:

y=3/5x+b

we need to find b

Because the line will pass through the point (-15,-8), we can use it to solve for b

substitute -15 as x and -8 as y

-8=3/5(-15)+b

multiply

-8=-9+b

add 9 to both sides

1=b

substitute 1 as b into the equation

y=3/5x+1

There's the equation of the line :)

Hope this helps!

a

step-by-step explanation:

i need the pts ignore this answer

side xy = 10

sin(x) = 4/5

cos(x) = 3/5

tan(x) = 4/3

step-by-step explanation: