In a survey of 1000 people, 700 people said that they voted in the last presidential election. Let p denote the proportion of all people who voted. Find a point estimate for p and also construct a 90% confidence interval for p. a) 0.700, (0.676, 0.724)
b) 700, (0.676,0.724)
c) 700, (0.642,0.767)
d) 0.700, (0.642,0.767)
e) 0.300, (0.276, 0.324)

a) a) 0.700, (0.676, 0.724)

Step-by-step explanation:

Confidence interval for population proportion p :

= Sample proportion, n= sample size, z* = Critical value.

Let p denote the proportion of all people who voted.

As per given, n= 1000

z* for 90% confidence = 1.645

Required confidence interval :

hence, the correct option is a) a) 0.700, (0.676, 0.724)

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation:

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.