Larry's father had to travel 385 miles to a work project. If he left at 8 A. M., travelling at a speed of 55 mph, how far would he be by noon?​

220 miles

Step-by-step explanation:

Given the following data;

Distance = 385 miles

Take-off time = 8 AM

Speed = 55 mph

To find how far would he be by noon;

Speed can be defined as distance covered per unit time. Speed is a scalar quantity and as such it has magnitude but no direction.

Mathematically, speed is given by the formula;

Making time the subject of formula, we have;

Substituting into the equation, we have;

Time = 7 hours

This ultimately implies that, he covers 55 miles per hour.

Next, we would determine how far he would be by noon.

Noon = 12 PM

By noon, time = 12 - 8 = 4 hours

Distance = speed * time

Distance = 55 * 4

Distance = 220 miles

Therefore, Larry's father would have covered a distance of 220 miles by noon.

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

alot

step-by-step explanation:

its a wood chuck that can chuck wood