A philosophy professor assigns letter grades on a test according to the following scheme. A: Top 12% of scores B: Scores below the top 12% and above the bottom 57% C: Scores below the top 43% and above the bottom 19% D: Scores below the top 81% and above the bottom 5% F: Bottom 5% of scores Scores on the test are normally distributed with a mean of 66.5 and a standard deviation of 9.9. Find the minimum score required for an A grade. Round your answer to the nearest whole number, if necessary.

The minimum score required for an A grade is 80.

Step-by-step explanation:

According to the Question,

A: Top 12% of scores

B: Scores below the top 12% and above the bottom 57%

C: Scores below the top 43% and above the bottom 19%

D: Scores below the top 81% and above the bottom 5%

F: Bottom 5% of scores Scores on the test

And The normally distributed with a mean of 66.5 and a standard deviation of 9.9.

Now,

we have μ=66.5 , σ=9.9  

Top 12%, so at least the 100-12 = 88th percentile, which is the value of X when Z has a p-value of 0.88. So it is X when Z = 1.175.

⇒ Z = (X-μ)/σ

⇒ 1.175×9.9 = X-66.5

⇒ X=78.132

Rounding to the nearest whole number, the answer is 80.

The minimum score required for an A grade is 80.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!