Explain why the following function is not piecewise continuous ​

9514 1404 393

  the function has no finite limit at the left end of the interval (5, ∞)

Step-by-step explanation:

In order for the function to be piecewise continuous, it must have finite limits at the endpoints of each of the subintervals. Here, the function goes to infinity as x → 5+, so has no finite limit there.

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10