The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 parts per billion (ppb) and is rising at a rate of 0.1 ppb each year. In the second body of water the initial measure is 0.12 ppb and the rate of increase is 0.06 ppb each year. Which equation can be used to find y, the year in which both bodies of water have the same amount of mercury?

A. 0.05 – 0.1y = 0.12 – 0.06y

B. 0.05y + 0.1 = 0.12y + 0.06

C. 0.05 + 0.1y = 0.12 + 0.06y

D. 0.05y – 0.1 = 0.12y – 0.06

(answer needed asap)

Step-by-step explanation:

Given

(A)

(B)

-- it is negative, because it decreases

Required

When both will be equal

The current amount is calculated using:

Where:

For A, we have:

For B, we have:

Both are equal when:

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d