Which of the following systems of inequalities would produce the region indicated on the graph below?

A. y ≥ x + 1 ; y ≥ 10 ; x ≥ 0
B. y > x + 1 ; y ≤ 10 ; x ≥ 0
C. y < x + 1 ; y ≤ 10 ; x ≥ 0
D. y ≥ x + 1 ; y < 10 ; x ≥ 0

y > x + 1 ; y ≤ 10 ; x ≥ 0

Step-by-step explanation:

First, we need to get the equation of the straight line. The equation of the straight line is expressed as y = mx+c

m is the slope

c is the y-intercept

Using the coordinate points (0, 1) and (1,2)

m = (2-1)/(1-0)

m = 1/1 = 1

y-intercept c = 1 (the point where the line cuts the y-axis)

Substitute;

Since y = mx+c, then y = 1x + 1

y = x+1

Since the line is a broken line and shaded above, then y > x+1

Also, the point shaded on the graph indicates y ≤ 10 ; x ≥ 0

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

b

step-by-step explanation:

u take $75 minus $60.the anwer/original($75)multiply by 100