Xy'=yln y/x
y'= (2xy)/ (x^2- x^2)
please
thank you so much!...
Mathematics, 26.07.2021 19:10 xxtonixwilsonxx
Xy'=yln y/x
y'= (2xy)/ (x^2- x^2)
please
thank you so much!
Answers: 1
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John checked his watch and said that it is thursday, 7 am. what will the day and time be 2006 hours plzzz i will give you 100 points
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Simplify (8x2 − 1 + 2x3) − (7x3 − 3x2 + 1). −5x3 + 11x2 − 2 5x3 − 11x2 + 2 x3 + 2x2 + x3 x3 − 2x2 − x3
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