Select the correct answer from each drop-down menu. The asymptote of the function f(x) = 3x + 1 – 2 is Its y-intercept is

-2

(0, 1)

Step-by-step explanation:

Giveb the function :

F(x) = 3^x + 1 – 2

To obtain the asymptote, take the limit of f(x) as x as tends to ∞

3^(∞+1) - 2 = 0 - 2

Hence,

y = 0 - 2.

y = - 2

The y intercept, this is the value of y when x = 0

Hence, put x = 0

F(0) = 3^(0 + 1) – 2

f(0) = 3^1 - 2

f(0) = 3 - 2

f(0) = 1

Y - intercept = (0, 1)

answer: 1 + 1 = 11

step-by-step explanation:

pls refer ro the top for answer