If (a+b)=3 and ab=2, find the value of a2+b2

so a^2 + b^2 = 5

Step-by-step explanation:

(a+b) = 3

ab = 2

so

(a+b)^2 = 3^2

a^2 + 2ab + b^2 = 9

or, a^2 + 2*2 + b^2 = 9

or, a^2 + 4 + b^2 = 9

or, a^2 +b^2 = 9-4 = 5

at least two

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.