Please help :( Given that sin(2x) +cos(2x)=1+sin(x) and that sin (x) does not equal to 0, show that 2(cosx-sinx)=1​

steps below

Step-by-step explanation:

sin(2x) +cos(2x)=1+sin(x)

2sinxcosx + (1 - 2sin²x) = 1 + sinx

(2sinxcosx  - 2sin²x) +1 = 1 + sinx

2sinx(cosx-sinx) + 1 = 1 + sinx  .. minus 1 both side

2sinx(cosx-sinx) = sinx    ... sinx ≠ 0, divide sinx both side

2(cosx-sinx) = 1

step-by-step explanation:

do you have a copy of the table?