Suppose ΔDEF ≅ΔLMN. What congruence statement is also true? ΔDEF ≅ΔLNM

ΔFED ≅ΔMNL

ΔEFD ≅ΔLNM

ΔEDF ≅ΔMLN

Step-by-step explanation:

If, ΔDEF ≅ΔLMN

So,

D <--> L

E <--> M

F <--> N

Hence,

ΔEDF ≅ΔMLN is correct

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

take it another