Is it possible to find 3 consecutive even integers whose sum is 40? Why?

The three odd integers are represented by

x

x + 2

x + 4

The sum is 40 more than the smallest value

x

+

(

x

+

2

)

+

(

x

+

4

)

=

x

+

40

x

+

x

+

2

+

x

+

4

=

x

+

40

3

x

+

6

=

x

+

40

2

x

=

34

x

=

17

17 + 19 + 21 = 57

17 = 57 - 40

1st part is 64,000,000

2nd part 500,000

step-by-step explanation:

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

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