The perimeter of a rectangle is 44 inches. If the length is 1 more than twice the width, what is the length and width? Only algebraic solution is accepted

The width is 7 inches, the length is 15 inches

Step-by-step explanation:

If the width is x inches, then the length is 2x+1 inches. Since the perimeter of a rectangle is 2 times the width plus 2 times the length, the perimeter will be 2x+2(2x+1), which simplifies to 6x+2. Since the perimeter is 44 inches, we get the equation 6x+2=44, which makes x=7. So, the width is 7 and the length is 15.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet