Geometry Question: Given that segment BE is perpendicular to segment AD, segment AC is perpendicular to segment BD, segment AC is congruent to segment BE, and segment DE is congruent to segment EC; Prove: Triangle DEC is equilateral (reference #16 in picture)

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

- (2, -7)

- lines r and s and lines t and u must be parallel

too many. (jk)

31 v bucks

step-by-step explanation:

since you bought 25 on friday and 6 on tuesday, you can just add them up.

25+6=31

check your work.

31-6=25

i hope this !

-yand3r3