The hypotenuse of a right triangle is 5 meters longer than one of its legs. The other leg is 6 meters. Find the length of the other leg, and round to the nearest tenth of an inch.

Use Pythagorean theorm.

a^2 + b^2 = c^2 (c is hypotenuse).

Let c = 5+b (because in the question it says the hypotenuse is one leg plus 5 more meters) ; we will solve for b and say it's the leg we don't know.

We will say A is the "other leg" we know, which is 6.

6^2 + b^2 = (5+b)^2

We get b = 1.1

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.