A football is thrown upward with an initial velocity of 50 feet per second from a height of 100 feet. The height of the object t seconds after it is thrown is glven by the function h(t) = -16t2 + 50t + 100. Determine the ball's average velocity from t = 0 to t = 3 seconds. 1) 2ft/s
2) -2 ft/s
3) -1.2 ft/s
4) 5 ft/s

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it

i need more details sorry

step-by-step explanation:

12.4, 12.387, 12.26, 12.252, 6.241, 6.2, 6.015, 6.009, 1.411, 1.2, 1.056, 1.007, 0.31,   0.13, 0.5, 0.04

step-by-step explanation:

ur welcome : )