Y=3 - 1/2x mathswatch help me please plot on graph

  see attached

Step-by-step explanation:

Your equation is in slope-intercept form, ...

  y = mx + b . . . . line with slope m and y-intercept b

with m = -1/2 and b = 3.

This tells you the point y=3 on the y-axis is one point on the graph. (That is the y-intercept.) It also tells you the line decreases 1 unit for each 2 units to the right.

  m = rise/run = -1/2   ⇒   rise = -1 for run = 2

So, another point that is 2 right an 1 down from (0, 3) is (2, 2). Your line will go through these two points. Plot them and draw the line through them.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk