Which statement is true about the discontinuities of the function f(x)? f (x) = StartFraction x + 1 Over 6 x squared minus 7 x minus 3 EndFraction There are asymptotes at x = three-halves and x = negative one-third. There are holes at x = three-halves and x = negative one-third. There are asymptotes at x = negative three-halves and x = one-third. There are holes at x = negative three-halves and x = one-third.

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation:

80% of the cookies

step-by-step explanation:

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

i think the answer would be c