If f(x) = 2x^3 + 5, then lim f(x)-f(0)/x^3= (A) 0
(B) 1
(C) 2
(D) 3
(E) The limit does not exist.
(explain the steps)

you can not drow on this

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

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i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

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step-by-step explanation: