The figure is a square based pyramid. Total surface area of the pyramid is 9072m³. If the length of the side of the square base is 56 cm , find the volume of the pyramid. Help!! :)

The volume of the pyramid=47040

Solution Given:

The total surface area of the pyramid =

let the height be AB be h.

length of side[l]=56 m

The volume of the pyramid=?

let slant height be AC=a.

and BC=b

we have,

The perimeter of base[P]=4l=4*56=224m

BC=28m

Now;

The total surface area of the pyramid =

lateral= surface area +base area=

now

By using Pythagoras law;

h=45m

now,

The volume  of the pyramid=

Step-by-step explanation:

246

step-by-step explanation:

134.6 us dollars

step-by-step explanation:

1 us dollar = 1.33 canadian dollars

so, 150 us dollars = 150 × 1.33 = $199.5.

in canada, the money mitchell spent = 20 canadian dollars.

remaining canadian dollars with him = 199.5 - 20 = 179.5.

after mitchell returned to us, he exchanged the remaining canadian dollars to us dollars.

179.5 canadian dollars = 179.5 × 0.75 = 134.6 us dollars.