If a randomly selected orphaned pet in a St. Louis animal shelter is a dog of one the types shown in the table, what is the probability that it is a mastiff? A. 15.30%
B. 18.15%
C. 21.04%
D. 26.65%

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

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your answer is b.

x = 33.9

y = 65.6

step-by-step explanation:

8(1/6)

step-by-step explain:

49/6= 48

8 (1/6)